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The Mathematics of Maybe: Introduction to Probability: CBSE Class 9 Mathematics practice questions

Practise 50 questions on The Mathematics of Maybe: Introduction to Probability, free, with an explanation for each answer.

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Sample questions

Two friends look at the same sky. Asha says, “It is bright and sunny, so rain is unlikely.” Ravi says, “It is very hot, so I think it may rain later.” Each of them judges the chance of rain only from what they see. They do not count trials or equal outcomes. What kind of probability are they giving?

Two friends and a sky with a sun and a cloud
  1. Theoretical probability, because all outcomes are equally likely
  2. Experimental probability, because they repeated an experiment many times
  3. Subjective probability, a personal judgement based on the evidence they see
  4. A probability of exactly 12\dfrac{1}{2}, because it either rains or it does not
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C. Subjective probability, a personal judgement based on the evidence they see

Estimates based on how a person reads the situation are subjective probability. Rain is not an equally likely two-outcome event, so the idea that "rain or no rain" must be 12\dfrac{1}{2} is a common slip. Experimental and theoretical probability need repeated trials or equally likely outcomes, which neither friend used.

A fair die is rolled 6000 times. About how many times would you expect a 4 to appear?

A die rolling and showing different faces
  1. About 15001500 times
  2. About 10001000 times
  3. About 960960 times
  4. About 600600 times
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B. About 10001000 times

For a fair die P(4)=16P(4) = \dfrac{1}{6}, and in the long run the share of 4s gets close to this (the Law of Large Numbers). Expected count =16×6000=1000= \dfrac{1}{6} \times 6000 = 1000. Dividing 6000 by 4 gives 15001500, and 960960 would come from reusing the experimental 0.160.16 from only 50 rolls.

A teacher picks a sample of 30 sweets from a large bag of 600 sweets. The sample has 10 red, 8 green, 7 yellow and 5 blue. Based on the sample, about how many yellow sweets are in the whole bag?

Rows of coloured sweets with a number for each colour
  1. 140140
  2. 100100
  3. 200200
  4. ≈86\approx 86
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A. 140140

P(yellow)=730P(\text{yellow}) = \dfrac{7}{30}, so the estimate is 730×600=140\dfrac{7}{30} \times 600 = 140. Using the blue count gives 530×600=100\dfrac{5}{30} \times 600 = 100, using red gives 200200, and dividing 600÷7≈86600 \div 7 \approx 86 ignores the sample size of 30.

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