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Predicting What Comes Next: Exploring Sequences and Progressions: CBSE Class 9 Mathematics practice questions

Practise 50 questions on Predicting What Comes Next: Exploring Sequences and Progressions, free, with an explanation for each answer.

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Sample questions

These dot triangles show the first four triangular numbers: 1, 3, 6, 10. How many dots are needed for Stage 5?

Dot triangles with one, two, three and four rows, and an empty dashed slot for the next stage
  1. 14
  2. 15
  3. 16
  4. 13
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B. 15

Each triangular number is the sum of the counting numbers up to its stage: 1+2+3+4+5=151+2+3+4+5 = 15. The gaps between terms grow 2,3,4,5,…2, 3, 4, 5, \dots, so after 1010 we add 55. Adding 44 again gives 1414 (forgetting the gap grows), and 1616 is the next square number, not triangular.

For the sequence tn=3n−7t_n = 3n - 7, which term number is 332332?

A function machine that takes a position number n and gives a term
  1. 111
  2. 108
  3. 113
  4. 339
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C. 113

Set 3n−7=3323n - 7 = 332, so 3n=3393n = 339 and n=113n = 113. So 332332 is the 113th term. Dividing 332332 by 33 and rounding gives 111111, subtracting 77 instead of adding gives 108108, and 339339 is the value of 3n3n, not the position nn.

An AP has 5050 terms. Its third term is 1212 and its last term is 106106. What is the 29th term?

A strip of 50 terms with the third term, 29th term and last term flagged
  1. 64
  2. 66
  3. 58
  4. 62
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A. 64

Subtracting gives 47d=9447d = 94, so d=2d = 2 and a=12−4=8a = 12 - 4 = 8. Then t29=8+28×2=64t_{29} = 8 + 28 \times 2 = 64. Using a+29d=66a + 29d = 66 is the ndnd slip, 29×2=5829 \times 2 = 58 forgets aa, and 8+27×2=628 + 27 \times 2 = 62 is one term too early.

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