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Real Numbers: CBSE Class 10 Mathematics practice questions

Practise 50 questions on Real Numbers, free, with an explanation for each answer.

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Sample questions

The tiles show 210=2×3×5×7210 = 2\times3\times5\times7 written in three different orders. Which statement is the Fundamental Theorem of Arithmetic?

Prime tiles 2, 3, 5, 7 arranged in three orders, each giving 210
  1. Every natural number can be written as a product of primes in several different ways
  2. Every composite number is a product of primes, but each different order gives a different factorisation
  3. Every composite number is a product of distinct primes, each used only once
  4. Every composite number can be written as a product of primes, and this factorisation is unique apart from the order of the primes
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D. Every composite number can be written as a product of primes, and this factorisation is unique apart from the order of the primes

The theorem has two parts: a composite number can be factorised into primes, and the factorisation is unique except for the order of the factors. The three rows show the same primes in different orders, so they count as one factorisation. Primes may repeat (for example 12=2×2×312 = 2\times2\times3), so the last option is false.

Using the factor tree, write 24752475 as a product of powers of primes.

Factor tree of 2475 with leaves 5, 5, 3, 3 and 11
  1. 32×52×113^2\times5^2\times11
  2. 3×5×113\times5\times11
  3. 32×5×113^2\times5\times11
  4. 32×52×1123^2\times5^2\times11^2
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A. 32×52×113^2\times5^2\times11

The leaves are 5,5,3,3,115,5,3,3,11. Grouping equal primes: 2475=32×52×112475 = 3^2\times5^2\times11 (check: 9×25×11=24759\times25\times11 = 2475). Writing each prime once gives only 165, using one 5 gives 495, and squaring 11 gives 2722527225. Every exponent must match how often the prime appears.

Use the prime powers in the table to find LCM(540,1176)\text{LCM}(540, 1176).

Prime powers of 540 and 1176
  1. 52920
  2. 635040
  3. 7560
  4. 12
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A. 52920

540=22×33×5540 = 2^2\times3^3\times5 and 1176=23×3×721176 = 2^3\times3\times7^2. Greatest powers: 23,33,51,722^3, 3^3, 5^1, 7^2, so LCM=8×27×5×49=52920\text{LCM} = 8\times27\times5\times49 = 52920. Using 717^1 gives 7560, the product 635040635040 counts the shared factor 12 twice, and 1212 is the HCF.

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