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Areas Related to Circles: CBSE Class 10 Mathematics practice questions

Practise 50 questions on Areas Related to Circles, free, with an explanation for each answer.

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Sample questions

A sector of a circle of radius rr has angle θ\theta (in degrees) at the centre. Its area is

A sector whose angle at the centre opens and closes
  1. θ180×πr2\dfrac{\theta}{180}\times\pi r^2
  2. θ360×2πr\dfrac{\theta}{360}\times 2\pi r
  3. θ360×πr2\dfrac{\theta}{360}\times\pi r^2
  4. θ360×πr\dfrac{\theta}{360}\times\pi r
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C. θ360×πr2\dfrac{\theta}{360}\times\pi r^2

By the unitary method, 360∘360^\circ gives πr2\pi r^2, so 1∘1^\circ gives πr2360\dfrac{\pi r^2}{360} and θ∘\theta^\circ gives θ360×πr2\dfrac{\theta}{360}\times\pi r^2. The option with 2πr2\pi r is the arc length, the one with θ/180\theta/180 doubles the area, and πr\pi r forgets to square the radius.

The circumference of a circle is 4444 cm. Find the area of its quadrant (one-fourth of the circle). (Use π=227\pi=\frac{22}{7}.)

A quadrant of a circle whose whole circumference is 44 cm
  1. 38.538.5 cm2^2
  2. 154154 cm2^2
  3. 7777 cm2^2
  4. 2525 cm2^2
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A. 38.538.5 cm2^2

2πr=44⇒r=72\pi r=44 \Rightarrow r=7 cm. A quadrant is 14\tfrac14 of the circle: 14×227×49=38.5\tfrac14\times\tfrac{22}{7}\times 49 = 38.5 cm2^2. The value 154154 is the whole circle, 7777 is a semicircle, and 2525 is the perimeter of the quadrant (11+7+711+7+7), not its area.

A circle has radius 1414 cm. A sector of this circle has area 7777 cm2^2. Find the angle of the sector. (Use π=227\pi=\frac{22}{7}.)

A sector of radius 14 cm and area 77 square centimetres
  1. 90∘90^\circ
  2. 45∘45^\circ
  3. 180∘180^\circ
  4. 8∘8^\circ
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B. 45∘45^\circ

πr2=227×196=616\pi r^2=\dfrac{22}{7}\times196=616, so θ360=77616=18\dfrac{\theta}{360}=\dfrac{77}{616}=\dfrac18 and θ=45∘\theta=45^\circ. Using θ/180\theta/180 gives 90∘90^\circ, using r=7r=7 gives 180∘180^\circ, and reading 18\tfrac18 as 88 gives 8∘8^\circ.

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