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Elections: CBSE Class 9 Politics practice questions

Practise 50 questions on Elections, free, with an explanation for each answer.

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Sample questions

Gurmat was elected class representative (CR) in Grade 8. Now the class is in Grade 9. Can she simply carry on as CR without facing a fresh election?

A classroom election with a ballot box and students in a queue
  1. Yes. Once elected, a representative may stay on for as long as she likes
  2. Yes, as long as the class teacher agrees
  3. No. Representatives must face periodic elections, so the people they speak for can hold them accountable
  4. No, because a student is allowed to be CR only once in school
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C. No. Representatives must face periodic elections, so the people they speak for can hold them accountable

The chapter answers this case with a clear No. Elected representatives are accountable to the people, and regular, periodic elections are how citizens renew or withdraw their mandate. The same logic applies to a government: it cannot continue beyond its prescribed term without seeking the people's mandate again. A teacher's approval cannot replace the voters' choice, and nothing in the idea limits a person to one term.

Constituency 14 elects its member by FPTP. Using the result board, who wins, and with what share of the votes polled?

A result board with votes for Party A, B and C and the total votes polled
  1. Party A, with 38% of the votes polled
  2. Nobody yet. A second round is needed because no one crossed 50%
  3. Party A, with 41.8% of the votes polled
  4. Party A, with 62% of the votes polled
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A. Party A, with 38% of the votes polled

Under FPTP the highest vote total wins, so Party A (41,800) wins. Its share is 41,8001,10,000×100=38%\dfrac{41{,}800}{1{,}10{,}000}\times 100 = 38\%. A run-off at 50% belongs to the majority system, not FPTP. 41.8% comes from wrongly dividing by 1,00,000. 62% is the share of votes against A (100−38100 - 38).

A State Assembly has 250 seats. Party A won 118, Party B 92 and Party C 40. To form a government on its own, a party needs a majority. How many more seats would Party A have needed?

A semicircular assembly of 250 seats shared by three parties
  1. 7 more
  2. 8 more
  3. 49 more
  4. None, because the largest party always governs alone
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B. 8 more

A majority means more than half: half of 250 is 125, so the majority mark is 125+1=126125 + 1 = 126. Party A needs 126−118=8126 - 118 = 8 more seats. '7' uses 125, which is only a tie, not a majority. '49' uses a two-thirds mark (167−118167 - 118). Being the largest party is not enough: without 126 seats, A would need support from others, as in a coalition.

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